What are the solutions to the equation x^2=-8x ?

The solutions to the equation x^2=-8x are x=0,x=-8

Find the zeros of x^2=-8x

The zeros of x^2=-8x are x=0,x=-8

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x^{2} = - 8 x

x = 0, x = - 8

Solution steps

x^{2} = - 8 x

Move

8 x

to the left side

x^{2} + 8 x = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 8 \pm 8 ^{2} - 4 \cdot 1 \cdot 0}{2 \cdot 1}

8^{2} - 4 \cdot 1 \cdot 0 = 8

x_{1, 2} = \frac{- 8 \pm 8}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 8 + 8}{2 \cdot 1}, x_{2} = \frac{- 8 - 8}{2 \cdot 1}

x = \frac{- 8 + 8}{2 \cdot 1} : 0

x = \frac{- 8 - 8}{2 \cdot 1} : - 8

The solutions to the quadratic equation are:

x = 0, x = - 8

- 9 x + 7 = - 6 x + 37

\frac{4 ( c ^{- 2} ) ^{4}}{12 c ^{- 1}}

12 z^{2} - 6 z + 42

7 x^{2} - x + 6 \geq 0

\frac{2}{4} \cdot \frac{2}{4}

What are the solutions to the equation x^2=-8x ?
The solutions to the equation x^2=-8x are x=0,x=-8
Find the zeros of x^2=-8x
The zeros of x^2=-8x are x=0,x=-8