What is expand (x-3)(2x^2+6x-7) ?

The solution to expand (x-3)(2x^2+6x-7) is 2x^3-25x+21

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

expand (x-3)(2x^2+6x-7)

expand

(x - 3) (2 x^{2} + 6 x - 7)

2 x^{3} - 25 x + 21

Solution steps

(x - 3) (2 x^{2} + 6 x - 7)

Distribute parentheses

= x \cdot 2 x^{2} + x \cdot 6 x + x (- 7) - 3 \cdot 2 x^{2} - 3 \cdot 6 x - 3 (- 7)

Simplify

x \cdot 2 x^{2} + x \cdot 6 x + x (- 7) - 3 \cdot 2 x^{2} - 3 \cdot 6 x - 3 (- 7) : 2 x^{3} - 25 x + 21

= 2 x^{3} - 25 x + 21

x y^{2} 54 x^{6} y^{5}

\frac{1}{1 0 ^{- 8}}

(x^{2} y^{- 3}) (x^{- 5} y^{3})

16 y^{5} z^{5} - 29 x^{2} y^{4} z^{3}

\frac{7}{10} \div 2

What is expand (x-3)(2x^2+6x-7) ?
The solution to expand (x-3)(2x^2+6x-7) is 2x^3-25x+21