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Popular >

x^2-8x+16>= 0

Solution

x^{2} - 8 x + 16 \geq 0

Solution

True for all x

+1

Interval Notation

(- \infty, \infty)

Solution steps

x^{2} - 8 x + 16 \geq 0

Factor

x^{2} - 8 x + 16 : (x - 4)^{2}

(x - 4)^{2} \geq 0

If n is even,

u^{n} \geq 0

for all

u

True for all x

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1 - \frac{1}{1 - \frac{1}{1 - \frac{2}{5}}}

y^{2} - 6 y + 34 = 0

Frequently Asked Questions (FAQ)

What is x^2-8x+16>= 0 ?
The solution to x^2-8x+16>= 0 is True for all x