What is 2(a+1)^2-(a+1)+4 ?

The solution to 2(a+1)^2-(a+1)+4 is 2a^2+3a+5

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simplify 2(a+1)^2-(a+1)+4

simplify

2 (a + 1)^{2} - (a + 1) + 4

2 a^{2} + 3 a + 5

Solution steps

2 (a + 1)^{2} - (a + 1) + 4

Apply the distributive law:

- (a + b) = - a - b

- (a + 1) = - a - 1

= 2 (a + 1)^{2} - a - 1 + 4

Expand

2 (a + 1)^{2} : 2 a^{2} + 4 a + 2

= 2 a^{2} + 4 a + 2 - a - 1 + 4

Group like terms

= 2 a^{2} + 4 a - a + 2 - 1 + 4

Add similar elements:

4 a - a = 3 a

= 2 a^{2} + 3 a + 2 - 1 + 4

Add the numbers:

2 - 1 + 4 = 5

= 2 a^{2} + 3 a + 5

(8 m)^{2} \cdot m^{- 6}

- 9 + (- 15)

32 (- 2)^{- 5}

4 i (- 7 + i)

13 a - 26 b + 39 c