What is sqrt(4a^2+4b^2) ?

The solution to sqrt(4a^2+4b^2) is 2sqrt(a^2+b^2)

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simplify sqrt(4a^2+4b^2)

simplify

4 a^{2} + 4 b^{2}

2 a^{2} + b^{2}

Solution steps

4 a^{2} + 4 b^{2}

Factor out common term

4

= 4 (a^{2} + b^{2})

Apply radical rule:

ab = a b,

assuming

a \geq 0, b \geq 0

4 (a^{2} + b^{2}) = 4 a^{2} + b^{2}

= 4 a^{2} + b^{2}

4 = 2

= 2 a^{2} + b^{2}

(f + g) (5)

\frac{( 2 + 3 i )}{( 1 + i )}

1015

\frac{5 ab + a}{5 ab}

- 50 \frac{1}{2} + (- 12.3)