What is (2x^3+4x+7)+(2x^2+5x-6) ?

The solution to (2x^3+4x+7)+(2x^2+5x-6) is 2x^3+2x^2+9x+1

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simplify (2x^3+4x+7)+(2x^2+5x-6)

simplify

(2 x^{3} + 4 x + 7) + (2 x^{2} + 5 x - 6)

2 x^{3} + 2 x^{2} + 9 x + 1

Solution steps

(2 x^{3} + 4 x + 7) + (2 x^{2} + 5 x - 6)

Simplify

(2 x^{3} + 4 x + 7) + (2 x^{2} + 5 x - 6) : 2 x^{3} + 4 x + 7 + 2 x^{2} + 5 x - 6

= 2 x^{3} + 4 x + 7 + 2 x^{2} + 5 x - 6

Group like terms

= 2 x^{3} + 2 x^{2} + 4 x + 5 x + 7 - 6

Add similar elements:

4 x + 5 x = 9 x

= 2 x^{3} + 2 x^{2} + 9 x + 7 - 6

Subtract the numbers:

7 - 6 = 1

= 2 x^{3} + 2 x^{2} + 9 x + 1

\frac{58}{6}

(x + 9 y)^{2}

56 \cdot 9

3 (3)

4 x^{4} x^{4}

What is (2x^3+4x+7)+(2x^2+5x-6) ?
The solution to (2x^3+4x+7)+(2x^2+5x-6) is 2x^3+2x^2+9x+1