What is (3x^2-2x-5)+(2x^2+x-10) ?

The solution to (3x^2-2x-5)+(2x^2+x-10) is 5x^2-x-15

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simplify (3x^2-2x-5)+(2x^2+x-10)

simplify

(3 x^{2} - 2 x - 5) + (2 x^{2} + x - 10)

5 x^{2} - x - 15

Solution steps

(3 x^{2} - 2 x - 5) + (2 x^{2} + x - 10)

Simplify

(3 x^{2} - 2 x - 5) + (2 x^{2} + x - 10) : 3 x^{2} - 2 x - 5 + 2 x^{2} + x - 10

= 3 x^{2} - 2 x - 5 + 2 x^{2} + x - 10

Group like terms

= 3 x^{2} + 2 x^{2} - 2 x + x - 5 - 10

Add similar elements:

3 x^{2} + 2 x^{2} = 5 x^{2}

= 5 x^{2} - 2 x + x - 5 - 10

Add similar elements:

- 2 x + x = - x

= 5 x^{2} - x - 5 - 10

Subtract the numbers:

- 5 - 10 = - 15

= 5 x^{2} - x - 15

(8 m - 6 n) - (- 3 m - 7 n)

- 4.9 (- 8)

- ∣ - 12 ∣

(9 x^{2} y^{- 4})^{\frac{1}{2}}

2 i (3 + 2 i)

What is (3x^2-2x-5)+(2x^2+x-10) ?
The solution to (3x^2-2x-5)+(2x^2+x-10) is 5x^2-x-15