What are the solutions to the equation x^2=-5x ?

The solutions to the equation x^2=-5x are x=0,x=-5

Find the zeros of x^2=-5x

The zeros of x^2=-5x are x=0,x=-5

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x^{2} = - 5 x

x = 0, x = - 5

Solution steps

x^{2} = - 5 x

Move

5 x

to the left side

x^{2} + 5 x = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 5 \pm 5 ^{2} - 4 \cdot 1 \cdot 0}{2 \cdot 1}

5^{2} - 4 \cdot 1 \cdot 0 = 5

x_{1, 2} = \frac{- 5 \pm 5}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 5 + 5}{2 \cdot 1}, x_{2} = \frac{- 5 - 5}{2 \cdot 1}

x = \frac{- 5 + 5}{2 \cdot 1} : 0

x = \frac{- 5 - 5}{2 \cdot 1} : - 5

The solutions to the quadratic equation are:

x = 0, x = - 5

- 31 p + 79 > - 59 p + 81 - 31 p + 79 > - 59 p + 81

(\frac{1}{2}) - 1

2 x^{2} - 5 x + 12 = 0

(y + 2)^{3} - (y - 1)^{3} = y (3 y + 4) + 8

3 ∣ 3 - 5 r ∣ - 3 = 18

What are the solutions to the equation x^2=-5x ?
The solutions to the equation x^2=-5x are x=0,x=-5
Find the zeros of x^2=-5x
The zeros of x^2=-5x are x=0,x=-5