What is expand (x^2-x-5)(x^2-3x+2) ?

The solution to expand (x^2-x-5)(x^2-3x+2) is x^4-4x^3+13x-10

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expand (x^2-x-5)(x^2-3x+2)

expand

(x^{2} - x - 5) (x^{2} - 3 x + 2)

x^{4} - 4 x^{3} + 13 x - 10

Solution steps

(x^{2} - x - 5) (x^{2} - 3 x + 2)

Distribute parentheses

= x^{2} x^{2} + x^{2} (- 3 x) + x^{2} \cdot 2 - x x^{2} - x (- 3 x) - x \cdot 2 - 5 x^{2} - 5 (- 3 x) - 5 \cdot 2

Simplify

x^{2} x^{2} + x^{2} (- 3 x) + x^{2} \cdot 2 - x x^{2} - x (- 3 x) - x \cdot 2 - 5 x^{2} - 5 (- 3 x) - 5 \cdot 2 : x^{4} - 4 x^{3} + 13 x - 10

= x^{4} - 4 x^{3} + 13 x - 10

\frac{x ^{2} + 3 x - 4}{x ^{2} + 4 x - 5}

2 - (x + 2)^{2}

- 11 (x^{- 3})^{2}

(\frac{1}{x}) (\frac{1}{x})

(0.12)^{2}

What is expand (x^2-x-5)(x^2-3x+2) ?
The solution to expand (x^2-x-5)(x^2-3x+2) is x^4-4x^3+13x-10