What are the solutions to the equation s^2+6s+25=0 ?

The solutions to the equation s^2+6s+25=0 are s=-3+4i,s=-3-4i

Find the zeros of s^2+6s+25=0

The zeros of s^2+6s+25=0 are s=-3+4i,s=-3-4i

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s^{2} + 6 s + 25 = 0

s = - 3 + 4 i, s = - 3 - 4 i

Solution steps

s^{2} + 6 s + 25 = 0

Solve with the quadratic formula

s_{1, 2} = \frac{- 6 \pm 6 ^{2} - 4 \cdot 1 \cdot 25}{2 \cdot 1}

Simplify

6^{2} - 4 \cdot 1 \cdot 25 : 8 i

s_{1, 2} = \frac{- 6 \pm 8 i}{2 \cdot 1}

Separate the solutions

s_{1} = \frac{- 6 + 8 i}{2 \cdot 1}, s_{2} = \frac{- 6 - 8 i}{2 \cdot 1}

s = \frac{- 6 + 8 i}{2 \cdot 1} : - 3 + 4 i

s = \frac{- 6 - 8 i}{2 \cdot 1} : - 3 - 4 i

The solutions to the quadratic equation are:

s = - 3 + 4 i, s = - 3 - 4 i

1 < 3

- \frac{1}{4} - 4

8 \leq ∣ 4 x - 8 ∣

\frac{( 3 k ^{4} ) ^{5}}{- 15 k ^{10}}

(- 2 - 3 i) \cdot (- 5 - 2 i)

What are the solutions to the equation s^2+6s+25=0 ?
The solutions to the equation s^2+6s+25=0 are s=-3+4i,s=-3-4i
Find the zeros of s^2+6s+25=0
The zeros of s^2+6s+25=0 are s=-3+4i,s=-3-4i