What is (9x^{-2}y^3z^{-4})^2 ?

The solution to (9x^{-2}y^3z^{-4})^2 is (81y^6)/(x^4z^8)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

simplify (9x^{-2}y^3z^{-4})^2

simplify

(9 x^{- 2} y^{3} z^{- 4})^{2}

\frac{81 y ^{6}}{x ^{4} z ^{8}}

Solution steps

(9 x^{- 2} y^{3} z^{- 4})^{2}

Apply exponent rule:

(a \cdot b)^{n} = a^{n} b^{n}

(9 x^{- 2} y^{3} z^{- 4})^{2} = 9^{2} (x^{- 2})^{2} (y^{3})^{2} (z^{- 4})^{2}

= 9^{2} (x^{- 2})^{2} (y^{3})^{2} (z^{- 4})^{2}

9^{2} = 81

= 81 (x^{- 2})^{2} (y^{3})^{2} (z^{- 4})^{2}

Simplify

(x^{- 2})^{2} : \frac{1}{x ^{4}}

= 81 \cdot \frac{1}{x ^{4}} (y^{3})^{2} (z^{- 4})^{2}

Simplify

(y^{3})^{2} : y^{6}

= 81 \cdot \frac{1}{x ^{4}} y^{6} (z^{- 4})^{2}

Simplify

(z^{- 4})^{2} : \frac{1}{z ^{8}}

= 81 \cdot \frac{1}{x ^{4}} y^{6} \frac{1}{z ^{8}}

Simplify

81 \cdot \frac{1}{x ^{4}} y^{6} \frac{1}{z ^{8}} : \frac{81 y ^{6}}{x ^{4} z ^{8}}

= \frac{81 y ^{6}}{x ^{4} z ^{8}}

- 4 x \cdot 2 x

\frac{1}{x - 1} + 2

3 \frac{1}{10}

\frac{1}{8} + \frac{1}{7}

- \frac{9}{4} - 2

What is (9x^{-2}y^3z^{-4})^2 ?
The solution to (9x^{-2}y^3z^{-4})^2 is (81y^6)/(x^4z^8)