What are the solutions to the equation 8x^2=5x-2 ?

The solutions to the equation 8x^2=5x-2 are x= 5/16+i(sqrt(39))/(16),x= 5/16-i(sqrt(39))/(16)

Find the zeros of 8x^2=5x-2

The zeros of 8x^2=5x-2 are x= 5/16+i(sqrt(39))/(16),x= 5/16-i(sqrt(39))/(16)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

8 x^{2} = 5 x - 2

x = \frac{5}{16} + i \frac{39}{16}, x = \frac{5}{16} - i \frac{39}{16}

Solution steps

8 x^{2} = 5 x - 2

Move

2

to the left side

8 x^{2} + 2 = 5 x

Move

5 x

to the left side

8 x^{2} + 2 - 5 x = 0

Write in the standard form

a x^{2} + b x + c = 0

8 x^{2} - 5 x + 2 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 5 ) \pm ( - 5 ) ^{2} - 4 \cdot 8 \cdot 2}{2 \cdot 8}

Simplify

(- 5)^{2} - 4 \cdot 8 \cdot 2 : 39 i

x_{1, 2} = \frac{- ( - 5 ) \pm 39 i}{2 \cdot 8}

Separate the solutions

x_{1} = \frac{- ( - 5 ) + 39 i}{2 \cdot 8}, x_{2} = \frac{- ( - 5 ) - 39 i}{2 \cdot 8}

x = \frac{- ( - 5 ) + 39 i}{2 \cdot 8} : \frac{5}{16} + i \frac{39}{16}

x = \frac{- ( - 5 ) - 39 i}{2 \cdot 8} : \frac{5}{16} - i \frac{39}{16}

The solutions to the quadratic equation are:

x = \frac{5}{16} + i \frac{39}{16}, x = \frac{5}{16} - i \frac{39}{16}

11 - 2 x = x + 2

6 x - 6 = 0

\frac{40 x ^{4} y + 16 x ^{2} y ^{3}}{60 x ^{2} y ^{2} - 36 x y ^{3}}

x - 1 \leq 4 x + 5

5 n + 3 = 14 - 6 n

What are the solutions to the equation 8x^2=5x-2 ?
The solutions to the equation 8x^2=5x-2 are x= 5/16+i(sqrt(39))/(16),x= 5/16-i(sqrt(39))/(16)
Find the zeros of 8x^2=5x-2
The zeros of 8x^2=5x-2 are x= 5/16+i(sqrt(39))/(16),x= 5/16-i(sqrt(39))/(16)