What are the solutions to the equation x^2-3x=7 ?

The solutions to the equation x^2-3x=7 are x=(3+sqrt(37))/2 ,x=(3-sqrt(37))/2

Find the zeros of x^2-3x=7

The zeros of x^2-3x=7 are x=(3+sqrt(37))/2 ,x=(3-sqrt(37))/2

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x^{2} - 3 x = 7

x = \frac{3 + 37}{2}, x = \frac{3 - 37}{2}

Decimal Notation

x = 4.54138 \dots, x = - 1.54138 \dots

Solution steps

x^{2} - 3 x = 7

Move

7

to the left side

x^{2} - 3 x - 7 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 3 ) \pm ( - 3 ) ^{2} - 4 \cdot 1 \cdot ( - 7 )}{2 \cdot 1}

(- 3)^{2} - 4 \cdot 1 \cdot (- 7) = 37

x_{1, 2} = \frac{- ( - 3 ) \pm 37}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 3 ) + 37}{2 \cdot 1}, x_{2} = \frac{- ( - 3 ) - 37}{2 \cdot 1}

x = \frac{- ( - 3 ) + 37}{2 \cdot 1} : \frac{3 + 37}{2}

x = \frac{- ( - 3 ) - 37}{2 \cdot 1} : \frac{3 - 37}{2}

The solutions to the quadratic equation are:

x = \frac{3 + 37}{2}, x = \frac{3 - 37}{2}

(\frac{r}{r ^{4}})^{3}

\frac{x ^{\frac{1}{2}}}{x ^{\frac{1}{6}}}

\frac{1}{8} x + \frac{3}{4} x = 12

6 x + 8 = 7 x + 13

\frac{n ^{2} - 14 n + 45}{n ^{2} - 10 n + 9}

What are the solutions to the equation x^2-3x=7 ?
The solutions to the equation x^2-3x=7 are x=(3+sqrt(37))/2 ,x=(3-sqrt(37))/2
Find the zeros of x^2-3x=7
The zeros of x^2-3x=7 are x=(3+sqrt(37))/2 ,x=(3-sqrt(37))/2