What is (3-2i)+[(4-5i)-(5+i)] ?

The solution to (3-2i)+[(4-5i)-(5+i)] is 2-8i

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simplify (3-2i)+[(4-5i)-(5+i)]

simplify

(3 - 2 i) + [(4 - 5 i) - (5 + i)]

2 - 8 i

Solution steps

(3 - 2 i) + ((4 - 5 i) - (5 + i))

Simplify

(3 - 2 i) + ((4 - 5 i) - (5 + i)) : 3 - 2 i + 4 - 5 i - (5 + i)

= 3 - 2 i + 4 - 5 i - (5 + i)

Group like terms

= - 2 i - 5 i - (5 + i) + 3 + 4

Add similar elements:

- 2 i - 5 i = - 7 i

= - 7 i - (5 + i) + 3 + 4

Add the numbers:

3 + 4 = 7

= - 7 i - (5 + i) + 7

Remove parentheses:

- (a + bi) = - a - bi

= - 7 i + - 5 - i + 7

Group like terms

= - 7 i - i - 5 + 7

Add similar elements:

- 7 i - i = - 8 i

= - 8 i - 5 + 7

Add the numbers:

- 5 + 7 = 2

= - 8 i + 2

Rewrite in standard complex form:

2 - 8 i

= 2 - 8 i

(1 + 2 i) + (2 - 3 i)

- 27 (- 7 - 2)

2^{x + 2} - 2^{x - 2}

\frac{84}{2}

f (∣ x ∣)