What is x^2(x+4)+3x(x+4)-70(x+4) ?

The solution to x^2(x+4)+3x(x+4)-70(x+4) is x^3+7x^2-58x-280

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simplify x^2(x+4)+3x(x+4)-70(x+4)

simplify

x^{2} (x + 4) + 3 x (x + 4) - 70 (x + 4)

x^{3} + 7 x^{2} - 58 x - 280

Solution steps

x^{2} (x + 4) + 3 x (x + 4) - 70 (x + 4)

Expand

x^{2} (x + 4) : x^{3} + 4 x^{2}

= x^{3} + 4 x^{2} + 3 x (x + 4) - 70 (x + 4)

Expand

3 x (x + 4) : 3 x^{2} + 12 x

= x^{3} + 4 x^{2} + 3 x^{2} + 12 x - 70 (x + 4)

Expand

- 70 (x + 4) : - 70 x - 280

= x^{3} + 4 x^{2} + 3 x^{2} + 12 x - 70 x - 280

Add similar elements:

4 x^{2} + 3 x^{2} = 7 x^{2}

= x^{3} + 7 x^{2} + 12 x - 70 x - 280

Add similar elements:

12 x - 70 x = - 58 x

= x^{3} + 7 x^{2} - 58 x - 280

e^{0} 0 + 3 e^{0}

csc (x) - tan (x) sin (x) cos (x)

- 20 x^{2} + 360 x + 1000

1 + \frac{x ^{3}}{6} + 5 x

143 + 305 \cdot 70 He ll oo

What is x^2(x+4)+3x(x+4)-70(x+4) ?
The solution to x^2(x+4)+3x(x+4)-70(x+4) is x^3+7x^2-58x-280