What is factor 125+27w^3 ?

The solution to factor 125+27w^3 is (3w+5)(9w^2-15w+25)

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factor 125+27w^3

factor

125 + 27 w^{3}

(3 w + 5) (9 w^{2} - 15 w + 25)

Solution steps

125 + 27 w^{3}

Write in the standard form

= 27 w^{3} + 125

Apply exponent rules

= (3 w)^{3} + 5^{3}

Apply Sum of Cubes Formula:

x^{3} + y^{3} = (x + y) (x^{2} - x y + y^{2})

(3 w)^{3} + 5^{3} = (3 w + 5) (3^{2} w^{2} - 5 \cdot 3 w + 5^{2})

= (3 w + 5) (3^{2} w^{2} - 5 \cdot 3 w + 5^{2})

Simplify

(3 w + 5) (3^{2} w^{2} - 5 \cdot 3 w + 5^{2}) : (3 w + 5) (9 w^{2} - 15 w + 25)

= (3 w + 5) (9 w^{2} - 15 w + 25)

\frac{2 p ^{2} - p - 15}{p ^{2} - 3 p}

2 x^{2} - x + 8 x - 4

\frac{ln ( 1 )}{ln ( 2 )}

\frac{94}{4}

\frac{94}{3}

What is factor 125+27w^3 ?
The solution to factor 125+27w^3 is (3w+5)(9w^2-15w+25)