What is factor (3x-1)^2-(x+1)^2 ?

The solution to factor (3x-1)^2-(x+1)^2 is 8x(x-1)

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factor (3x-1)^2-(x+1)^2

factor

(3 x - 1)^{2} - (x + 1)^{2}

8 x (x - 1)

Solution steps

(3 x - 1)^{2} - (x + 1)^{2}

Apply Difference of Two Squares Formula:

x^{2} - y^{2} = (x + y) (x - y)

(3 x - 1)^{2} - (x + 1)^{2} = ((3 x - 1) + (x + 1)) ((3 x - 1) - (x + 1))

= ((3 x - 1) + (x + 1)) ((3 x - 1) - (x + 1))

Simplify

((3 x - 1) + (x + 1)) ((3 x - 1) - (x + 1)) : 4 x (2 x - 2)

= 4 x (2 x - 2)

Factor

2 x - 2 : 2 (x - 1)

= 4 x \cdot 2 (x - 1)

Multiply the numbers:

4 \cdot 2 = 8

= 8 x (x - 1)

∣ 5 - x ∣ \geq - 6

52

\frac{1}{3} x - 4 = 1

300 \cdot \frac{π}{180}

(- 10)^{9}

What is factor (3x-1)^2-(x+1)^2 ?
The solution to factor (3x-1)^2-(x+1)^2 is 8x(x-1)