What is (3a^2-a+3)+(4a^2-5) ?

The solution to (3a^2-a+3)+(4a^2-5) is 7a^2-a-2

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simplify (3a^2-a+3)+(4a^2-5)

simplify

(3 a^{2} - a + 3) + (4 a^{2} - 5)

7 a^{2} - a - 2

Solution steps

(3 a^{2} - a + 3) + (4 a^{2} - 5)

Simplify

(3 a^{2} - a + 3) + (4 a^{2} - 5) : 3 a^{2} - a + 3 + 4 a^{2} - 5

= 3 a^{2} - a + 3 + 4 a^{2} - 5

Group like terms

= 3 a^{2} + 4 a^{2} - a + 3 - 5

Add similar elements:

3 a^{2} + 4 a^{2} = 7 a^{2}

= 7 a^{2} - a + 3 - 5

Subtract the numbers:

3 - 5 = - 2

= 7 a^{2} - a - 2

(2 x^{2} + y)^{2}

1825

2 + 2 + 2 + 2

\frac{( 4 x - x ^{2} ) - 3}{x - 1}

4 0^{\frac{1}{3}}