What are the solutions to the equation 6=(x-2)^2 ?

The solutions to the equation 6=(x-2)^2 are x=sqrt(6)+2,x=-sqrt(6)+2

Find the zeros of 6=(x-2)^2

The zeros of 6=(x-2)^2 are x=sqrt(6)+2,x=-sqrt(6)+2

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6 = (x - 2)^{2}

x = 6 + 2, x = - 6 + 2

Solution steps

6 = (x - 2)^{2}

Switch sides

(x - 2)^{2} = 6

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

x - 2 = 6 : x = 6 + 2

Solve

x - 2 = - 6 : x = - 6 + 2

The solutions to the quadratic equation are:

x = 6 + 2, x = - 6 + 2

48 \cdot 6

- \frac{2 ( 2 ) + 4}{3 + 4 ( - 1 )}

- 5 (4 x - 3) \leq - 65

b^{5} \cdot b^{8}

\frac{r ^{9}}{r ^{3}}

What are the solutions to the equation 6=(x-2)^2 ?
The solutions to the equation 6=(x-2)^2 are x=sqrt(6)+2,x=-sqrt(6)+2
Find the zeros of 6=(x-2)^2
The zeros of 6=(x-2)^2 are x=sqrt(6)+2,x=-sqrt(6)+2