What are the solutions to the equation w^2-15w+44=0 ?

The solutions to the equation w^2-15w+44=0 are w=11,w=4

Find the zeros of w^2-15w+44=0

The zeros of w^2-15w+44=0 are w=11,w=4

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w^{2} - 15 w + 44 = 0

w = 11, w = 4

Solution steps

w^{2} - 15 w + 44 = 0

Solve with the quadratic formula

w_{1, 2} = \frac{- ( - 15 ) \pm ( - 15 ) ^{2} - 4 \cdot 1 \cdot 44}{2 \cdot 1}

(- 15)^{2} - 4 \cdot 1 \cdot 44 = 7

w_{1, 2} = \frac{- ( - 15 ) \pm 7}{2 \cdot 1}

Separate the solutions

w_{1} = \frac{- ( - 15 ) + 7}{2 \cdot 1}, w_{2} = \frac{- ( - 15 ) - 7}{2 \cdot 1}

w = \frac{- ( - 15 ) + 7}{2 \cdot 1} : 11

w = \frac{- ( - 15 ) - 7}{2 \cdot 1} : 4

The solutions to the quadratic equation are:

w = 11, w = 4

- 15

(x - 2)^{2} = 28

32 = 13 - 4 x + 21

3 q^{2} = - 3

27 c^{3} - 125

What are the solutions to the equation w^2-15w+44=0 ?
The solutions to the equation w^2-15w+44=0 are w=11,w=4
Find the zeros of w^2-15w+44=0
The zeros of w^2-15w+44=0 are w=11,w=4