What is (x+1)(2x-4)+3x(6x-5) ?

The solution to (x+1)(2x-4)+3x(6x-5) is 20x^2-17x-4

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simplify (x+1)(2x-4)+3x(6x-5)

simplify

(x + 1) (2 x - 4) + 3 x (6 x - 5)

20 x^{2} - 17 x - 4

Solution steps

(x + 1) (2 x - 4) + 3 x (6 x - 5)

Expand

(x + 1) (2 x - 4) : 2 x^{2} - 2 x - 4

= 2 x^{2} - 2 x - 4 + 3 x (6 x - 5)

Expand

3 x (6 x - 5) : 18 x^{2} - 15 x

= 2 x^{2} - 2 x - 4 + 18 x^{2} - 15 x

Group like terms

= 2 x^{2} + 18 x^{2} - 2 x - 15 x - 4

Add similar elements:

2 x^{2} + 18 x^{2} = 20 x^{2}

= 20 x^{2} - 2 x - 15 x - 4

Add similar elements:

- 2 x - 15 x = - 17 x

= 20 x^{2} - 17 x - 4

(- \frac{1}{10})^{3}

\frac{1}{1} \cdot (- 1)

5 a + 5 b - 4 (a + b)

\frac{8}{8}

- \frac{3}{2} - 5

What is (x+1)(2x-4)+3x(6x-5) ?
The solution to (x+1)(2x-4)+3x(6x-5) is 20x^2-17x-4