What are the solutions to the equation 3+40x-16x^2=16 ?

The solutions to the equation 3+40x-16x^2=16 are x=(5-2sqrt(3))/4 ,x=(5+2sqrt(3))/4

Find the zeros of 3+40x-16x^2=16

The zeros of 3+40x-16x^2=16 are x=(5-2sqrt(3))/4 ,x=(5+2sqrt(3))/4

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

3 + 40 x - 16 x^{2} = 16

x = \frac{5 - 2 3}{4}, x = \frac{5 + 2 3}{4}

Decimal Notation

x = 0.38397 \dots, x = 2.11602 \dots

Solution steps

3 + 40 x - 16 x^{2} = 16

Move

16

to the left side

- 16 x^{2} + 40 x - 13 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 40 \pm 4 0 ^{2} - 4 ( - 16 ) ( - 13 )}{2 ( - 16 )}

4 0^{2} - 4 (- 16) (- 13) = 163

x_{1, 2} = \frac{- 40 \pm 16 3}{2 ( - 16 )}

Separate the solutions

x_{1} = \frac{- 40 + 16 3}{2 ( - 16 )}, x_{2} = \frac{- 40 - 16 3}{2 ( - 16 )}

x = \frac{- 40 + 16 3}{2 ( - 16 )} : \frac{5 - 2 3}{4}

x = \frac{- 40 - 16 3}{2 ( - 16 )} : \frac{5 + 2 3}{4}

The solutions to the quadratic equation are:

x = \frac{5 - 2 3}{4}, x = \frac{5 + 2 3}{4}

(32 x^{15} y^{5})^{- \frac{3}{5}}

x^{3} - 2 x^{2} - 13 x - 10

700 = 9 x - 0.02 x^{2}

(\frac{1}{64})^{\frac{3}{2}}

What are the solutions to the equation 3+40x-16x^2=16 ?
The solutions to the equation 3+40x-16x^2=16 are x=(5-2sqrt(3))/4 ,x=(5+2sqrt(3))/4
Find the zeros of 3+40x-16x^2=16
The zeros of 3+40x-16x^2=16 are x=(5-2sqrt(3))/4 ,x=(5+2sqrt(3))/4