What is factor 4+4x+x^2 ?

The solution to factor 4+4x+x^2 is (x+2)^2

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factor 4+4x+x^2

factor

4 + 4 x + x^{2}

(x + 2)^{2}

Solution steps

4 + 4 x + x^{2}

Write in the standard form

= x^{2} + 4 x + 4

Rewrite in the form of

a^{2} + 2 ab + b^{2} :

4 = 2^{2}

4 x = 2 x \cdot 2

= x^{2} + 2 x \cdot 2 + 2^{2}

Apply Perfect Square Formula:

a^{2} + 2 ab + b^{2} = (a + b)^{2}

x^{2} + 2 x \cdot 2 + 2^{2} = (x + 2)^{2}

= (x + 2)^{2}

\frac{4}{9} + \frac{4}{15}

245 - 125

(b + 4)^{2}

\frac{∣ - 2 ∣}{2}

(\frac{1 + i}{1 - i})^{5}