What is (16-b^4)/(2+b) ?

The solution to (16-b^4)/(2+b) is -(b^2+4)(b-2)

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simplify (16-b^4)/(2+b)

simplify

\frac{16 - b ^{4}}{2 + b}

- (b^{2} + 4) (b - 2)

Solution steps

\frac{16 - b ^{4}}{2 + b}

Factor

16 - b^{4} : - (b^{2} + 4) (b + 2) (b - 2)

= \frac{- ( b ^{2} + 4 ) ( b + 2 ) ( b - 2 )}{2 + b}

Apply the commutative law:

2 + b = b + 2

= \frac{- ( b ^{2} + 4 ) ( b + 2 ) ( b - 2 )}{b + 2}

Cancel the common factor:

b + 2

= - (b^{2} + 4) (b - 2)

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