What are the solutions to the equation r^2+2r+3=0 ?

The solutions to the equation r^2+2r+3=0 are r=-1+sqrt(2)i,r=-1-sqrt(2)i

Find the zeros of r^2+2r+3=0

The zeros of r^2+2r+3=0 are r=-1+sqrt(2)i,r=-1-sqrt(2)i

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r^{2} + 2 r + 3 = 0

r = - 1 + 2 i, r = - 1 - 2 i

Solution steps

r^{2} + 2 r + 3 = 0

Solve with the quadratic formula

r_{1, 2} = \frac{- 2 \pm 2 ^{2} - 4 \cdot 1 \cdot 3}{2 \cdot 1}

Simplify

2^{2} - 4 \cdot 1 \cdot 3 : 22 i

r_{1, 2} = \frac{- 2 \pm 2 2 i}{2 \cdot 1}

Separate the solutions

r_{1} = \frac{- 2 + 2 2 i}{2 \cdot 1}, r_{2} = \frac{- 2 - 2 2 i}{2 \cdot 1}

r = \frac{- 2 + 2 2 i}{2 \cdot 1} : - 1 + 2 i

r = \frac{- 2 - 2 2 i}{2 \cdot 1} : - 1 - 2 i

The solutions to the quadratic equation are:

r = - 1 + 2 i, r = - 1 - 2 i

63 + 9 y + 7 x + x y

\frac{3 ^{5}}{3 ^{3}}

(n + 1)!

0.001 = \frac{x + 1}{\frac{8000000}{8}}

What are the solutions to the equation r^2+2r+3=0 ?
The solutions to the equation r^2+2r+3=0 are r=-1+sqrt(2)i,r=-1-sqrt(2)i
Find the zeros of r^2+2r+3=0
The zeros of r^2+2r+3=0 are r=-1+sqrt(2)i,r=-1-sqrt(2)i