What is factor 2n^2+3n+1 ?

The solution to factor 2n^2+3n+1 is (2n+1)(n+1)

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factor 2n^2+3n+1

factor

2 n^{2} + 3 n + 1

(2 n + 1) (n + 1)

Solution steps

2 n^{2} + 3 n + 1

Break the expression into groups

= (2 n^{2} + n) + (2 n + 1)

Factor out

n

from

2 n^{2} + n : n (2 n + 1)

= n (2 n + 1) + (2 n + 1)

Factor out common term

(2 n + 1) : (2 n + 1) (n + 1)

= (2 n + 1) (n + 1)

36 y^{4}

\frac{11 !}{4 ! 4 ! 2 !}

(t - 2) h (t - 5)

(2 + 3 i) + (5 - 4 i)

15 - 2 (4 + 7 a) + 5 a