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Popular >

simplify sqrt(1^2+2^2+4^2)

Solution

simplify

1^{2} + 2^{2} + 4^{2}

Solution

21

+1

Decimal Notation

4.58257 \dots

Solution steps

1^{2} + 2^{2} + 4^{2}

1^{2} = 1

2^{2} = 4

4^{2} = 16

= 1 + 4 + 16

Add the numbers:

1 + 4 + 16 = 21

= 21

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Frequently Asked Questions (FAQ)

What is sqrt(1^2+2^2+4^2) ?
The solution to sqrt(1^2+2^2+4^2) is square root of 21