What is the answer to x/2-(2*(x+2))/7 =(x-3)/4 ?

The answer to x/2-(2*(x+2))/7 =(x-3)/4 is x=5

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x/2-(2*(x+2))/7 =(x-3)/4

\frac{x}{2} - \frac{2 \cdot ( x + 2 )}{7} = \frac{x - 3}{4}

x = 5

Solution steps

\frac{x}{2} - \frac{2 ( x + 2 )}{7} = \frac{x - 3}{4}

Multiply by LCM

14 x - 8 (x + 2) = 7 (x - 3)

Expand

- 8 (x + 2) : - 8 x - 16

14 x - 8 x - 16 = 7 (x - 3)

Add similar elements:

14 x - 8 x = 6 x

6 x - 16 = 7 (x - 3)

Expand

7 (x - 3) : 7 x - 21

6 x - 16 = 7 x - 21

Move

16

to the right side

6 x = 7 x - 5

Move

7 x

to the left side

- x = - 5

Divide both sides by

- 1

x = 5

\frac{x + 7}{7} = 10

s - 31 > 93

5 \leq \frac{3 x + 4}{2} < 11

x + 5 = 12

2 x^{4} - 2 u^{4} y^{4}

What is the answer to x/2-(2*(x+2))/7 =(x-3)/4 ?
The answer to x/2-(2*(x+2))/7 =(x-3)/4 is x=5
Solve for x: x/2-(2*(x+2))/7 =(x-3)/4
The solution is x=5