What is (3y^4)^3+2y^7-4y^{12} ?

The solution to (3y^4)^3+2y^7-4y^{12} is 23y^{12}+2y^7

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simplify (3y^4)^3+2y^7-4y^{12}

simplify

(3 y^{4})^{3} + 2 y^{7} - 4 y^{12}

23 y^{12} + 2 y^{7}

Solution steps

(3 y^{4})^{3} + 2 y^{7} - 4 y^{12}

Simplify

(3 y^{4})^{3} : 27 y^{12}

= 27 y^{12} + 2 y^{7} - 4 y^{12}

Group like terms

= 27 y^{12} - 4 y^{12} + 2 y^{7}

Add similar elements:

27 y^{12} - 4 y^{12} = 23 y^{12}

= 23 y^{12} + 2 y^{7}

y^{2} + 7 y - 170

(n^{2})^{2}

- 5 x^{2} + 20 x + 60

\frac{3}{10} \cdot \frac{3}{8}

\frac{1}{9} + \frac{7}{6}

What is (3y^4)^3+2y^7-4y^{12} ?
The solution to (3y^4)^3+2y^7-4y^{12} is 23y^{12}+2y^7