What is 1/(\frac{1){x+1}+1} ?

The solution to 1/(\frac{1){x+1}+1} is (x+1)/(x+2)

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simplify 1/(\frac{1){x+1}+1}

simplify

\frac{1}{\frac{1}{x + 1} + 1}

\frac{x + 1}{x + 2}

Solution steps

\frac{1}{\frac{1}{x + 1} + 1}

Join

\frac{1}{x + 1} + 1 : \frac{x + 2}{x + 1}

= \frac{1}{\frac{x + 2}{x + 1}}

Apply the fraction rule:

\frac{1}{\frac{b}{c}} = \frac{c}{b}

= \frac{x + 1}{x + 2}

\frac{1}{2}

\frac{- 25}{( - 5 )}

(- 1) + 4

(\frac{1}{cos ( x )})^{2}

\frac{1}{x - 2} - \frac{1}{x + 2}

What is 1/(\frac{1){x+1}+1} ?
The solution to 1/(\frac{1){x+1}+1} is (x+1)/(x+2)