What is (3^0x^2)/(y^{-4)z^0} ?

The solution to (3^0x^2)/(y^{-4)z^0} is x^2y^4

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simplify (3^0x^2)/(y^{-4)z^0}

simplify

\frac{3 ^{0} x ^{2}}{y ^{- 4} z ^{0}}

x^{2} y^{4}

Solution steps

\frac{3 ^{0} x ^{2}}{y ^{- 4} z ^{0}}

Simplify

3^{0} x^{2} : x^{2}

= \frac{x ^{2}}{y ^{- 4} z ^{0}}

Simplify

y^{- 4} z^{0} : \frac{1}{y ^{4}}

= \frac{x ^{2}}{\frac{1}{y ^{4}}}

Apply the fraction rule:

\frac{a}{\frac{b}{c}} = \frac{a \cdot c}{b}

= \frac{x ^{2} y ^{4}}{1}

Apply the fraction rule:

\frac{a}{1} = a

= x^{2} y^{4}

- 0.49

m^{3} - 3 m - 2

\frac{2}{1 - 2}

1 \frac{7}{16}

((x^{2} y^{- 2})^{- 1})^{- 1}