What is (2x^2+5x-7)/(x^2+3x-4) ?

The solution to (2x^2+5x-7)/(x^2+3x-4) is (2x+7)/(x+4)

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simplify (2x^2+5x-7)/(x^2+3x-4)

simplify

\frac{2 x ^{2} + 5 x - 7}{x ^{2} + 3 x - 4}

\frac{2 x + 7}{x + 4}

Solution steps

\frac{2 x ^{2} + 5 x - 7}{x ^{2} + 3 x - 4}

Factor

2 x^{2} + 5 x - 7 : (x - 1) (2 x + 7)

= \frac{( x - 1 ) ( 2 x + 7 )}{x ^{2} + 3 x - 4}

Factor

x^{2} + 3 x - 4 : (x - 1) (x + 4)

= \frac{( x - 1 ) ( 2 x + 7 )}{( x - 1 ) ( x + 4 )}

Cancel the common factor:

x - 1

= \frac{2 x + 7}{x + 4}

(x^{2} + 5 x + 25) (x - 5)

5 t - 10 t^{2}

- 3 x \cdot 3 x

\frac{2}{3} 27

What is (2x^2+5x-7)/(x^2+3x-4) ?
The solution to (2x^2+5x-7)/(x^2+3x-4) is (2x+7)/(x+4)