What is (\frac{x+8)/(x+3)-2}{x-2} ?

The solution to (\frac{x+8)/(x+3)-2}{x-2} is -1/(x+3)

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simplify (\frac{x+8)/(x+3)-2}{x-2}

simplify

\frac{\frac{x + 8}{x + 3} - 2}{x - 2}

- \frac{1}{x + 3}

Solution steps

\frac{\frac{x + 8}{x + 3} - 2}{x - 2}

Join

\frac{x + 8}{x + 3} - 2 : \frac{- x + 2}{x + 3}

= \frac{\frac{- x + 2}{x + 3}}{x - 2}

Apply the fraction rule:

\frac{\frac{a}{b}}{c} = \frac{a}{b \cdot c}

= \frac{- x + 2}{( x + 3 ) ( x - 2 )}

Cancel

\frac{- x + 2}{( x + 3 ) ( x - 2 )} : - \frac{1}{x + 3}

= - \frac{1}{x + 3}

(5^{- 1})^{3}

\frac{4 - 4}{2}

m^{2} - m - 90

\frac{1}{32} + \frac{1}{16}

\frac{- 1}{2} \cdot (- 1)

What is (\frac{x+8)/(x+3)-2}{x-2} ?
The solution to (\frac{x+8)/(x+3)-2}{x-2} is -1/(x+3)