What are the solutions to the equation 4x^2-8x=-1 ?

The solutions to the equation 4x^2-8x=-1 are x=(2+sqrt(3))/2 ,x=(2-sqrt(3))/2

Find the zeros of 4x^2-8x=-1

The zeros of 4x^2-8x=-1 are x=(2+sqrt(3))/2 ,x=(2-sqrt(3))/2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

4 x^{2} - 8 x = - 1

x = \frac{2 + 3}{2}, x = \frac{2 - 3}{2}

Decimal Notation

x = 1.86602 \dots, x = 0.13397 \dots

Solution steps

4 x^{2} - 8 x = - 1

Move

1

to the left side

4 x^{2} - 8 x + 1 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 8 ) \pm ( - 8 ) ^{2} - 4 \cdot 4 \cdot 1}{2 \cdot 4}

(- 8)^{2} - 4 \cdot 4 \cdot 1 = 43

x_{1, 2} = \frac{- ( - 8 ) \pm 4 3}{2 \cdot 4}

Separate the solutions

x_{1} = \frac{- ( - 8 ) + 4 3}{2 \cdot 4}, x_{2} = \frac{- ( - 8 ) - 4 3}{2 \cdot 4}

x = \frac{- ( - 8 ) + 4 3}{2 \cdot 4} : \frac{2 + 3}{2}

x = \frac{- ( - 8 ) - 4 3}{2 \cdot 4} : \frac{2 - 3}{2}

The solutions to the quadratic equation are:

x = \frac{2 + 3}{2}, x = \frac{2 - 3}{2}

125 w^{2} - 180

- \frac{1}{3} ∣ 6 - 5 x ∣ + 2 \geq 1

\frac{y + 3}{6} < 2

6 - 6 \frac{x}{5} < 18

- x^{2} + 4 x - 1 = 0

What are the solutions to the equation 4x^2-8x=-1 ?
The solutions to the equation 4x^2-8x=-1 are x=(2+sqrt(3))/2 ,x=(2-sqrt(3))/2
Find the zeros of 4x^2-8x=-1
The zeros of 4x^2-8x=-1 are x=(2+sqrt(3))/2 ,x=(2-sqrt(3))/2