What is factor x^5-4x^4-x^3+10x^2+2x-4 ?

The solution to factor x^5-4x^4-x^3+10x^2+2x-4 is (x+1)^2(x-2)(x^2-4x+2)

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factor x^5-4x^4-x^3+10x^2+2x-4

factor

x^{5} - 4 x^{4} - x^{3} + 10 x^{2} + 2 x - 4

(x + 1)^{2} (x - 2) (x^{2} - 4 x + 2)

Solution steps

x^{5} - 4 x^{4} - x^{3} + 10 x^{2} + 2 x - 4

Use the rational root theorem

= (x + 1) \frac{x ^{5} - 4 x ^{4} - x ^{3} + 10 x ^{2} + 2 x - 4}{x + 1}

\frac{x ^{5} - 4 x ^{4} - x ^{3} + 10 x ^{2} + 2 x - 4}{x + 1} = x^{4} - 5 x^{3} + 4 x^{2} + 6 x - 4

= (x + 1) (x^{4} - 5 x^{3} + 4 x^{2} + 6 x - 4)

Factor

x^{4} - 5 x^{3} + 4 x^{2} + 6 x - 4 : (x + 1) (x - 2) (x^{2} - 4 x + 2)

= (x + 1) (x + 1) (x - 2) (x^{2} - 4 x + 2)

Apply exponent rule:

aa = a^{2}

(x + 1) (x + 1) = (x + 1)^{2}

= (x + 1)^{2} (x - 2) (x^{2} - 4 x + 2)

4 ∣ t + 1 ∣ \geq 16

\frac{72}{6}

\frac{x}{4} + 1 = 7

0.3 x^{2} + 1.4 x = 0

What is factor x^5-4x^4-x^3+10x^2+2x-4 ?
The solution to factor x^5-4x^4-x^3+10x^2+2x-4 is (x+1)^2(x-2)(x^2-4x+2)