What is (x+1)^2-(x+1)-9 ?

The solution to (x+1)^2-(x+1)-9 is x^2+x-9

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simplify (x+1)^2-(x+1)-9

simplify

(x + 1)^{2} - (x + 1) - 9

x^{2} + x - 9

Solution steps

(x + 1)^{2} - (x + 1) - 9

Apply the distributive law:

- (a + b) = - a - b

- (x + 1) = - x - 1

= (x + 1)^{2} - x - 1 - 9

Expand

(x + 1)^{2} : x^{2} + 2 x + 1

= x^{2} + 2 x + 1 - x - 1 - 9

Group like terms

= x^{2} + 2 x - x + 1 - 1 - 9

Add similar elements:

2 x - x = x

= x^{2} + x + 1 - 1 - 9

Subtract the numbers:

1 - 1 - 9 = - 9

= x^{2} + x - 9

\frac{45 x 5}{5 15}

\frac{3 - 9 i}{9 i}

6 x - 7 - 4 (2 x - 5)

\frac{2}{3} \cdot 14

\frac{2}{3} \cdot 21