What is (2r^2+6r+7)-(3r^2+5r+8) ?

The solution to (2r^2+6r+7)-(3r^2+5r+8) is -r^2+r-1

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simplify (2r^2+6r+7)-(3r^2+5r+8)

simplify

(2 r^{2} + 6 r + 7) - (3 r^{2} + 5 r + 8)

- r^{2} + r - 1

Solution steps

(2 r^{2} + 6 r + 7) - (3 r^{2} + 5 r + 8)

Apply rule:

(a) = a

(2 r^{2} + 6 r + 7) = 2 r^{2} + 6 r + 7

= 2 r^{2} + 6 r + 7 - (3 r^{2} + 5 r + 8)

Apply the distributive law:

- (a + b) = - a - b

- (3 r^{2} + 5 r + 8) = - 3 r^{2} - 5 r - 8

= 2 r^{2} + 6 r + 7 - 3 r^{2} - 5 r - 8

Group like terms

= 2 r^{2} - 3 r^{2} + 6 r - 5 r + 7 - 8

Add similar elements:

2 r^{2} - 3 r^{2} = - r^{2}

= - r^{2} + 6 r - 5 r + 7 - 8

Add similar elements:

6 r - 5 r = r

= - r^{2} + r + 7 - 8

Subtract the numbers:

7 - 8 = - 1

= - r^{2} + r - 1

(x^{3 n} \cdot y^{2 m})^{2}

24 w^{2} - 22 w + 4

\frac{1}{5 - x}

\frac{3 x ^{4} - 15 x ^{3} + 24 x}{3 x}

2^{2} - 4

What is (2r^2+6r+7)-(3r^2+5r+8) ?
The solution to (2r^2+6r+7)-(3r^2+5r+8) is -r^2+r-1