What is expand (3x-4)(9x^2+12x+16) ?

The solution to expand (3x-4)(9x^2+12x+16) is 27x^3-64

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expand (3x-4)(9x^2+12x+16)

expand

(3 x - 4) (9 x^{2} + 12 x + 16)

27 x^{3} - 64

Solution steps

(3 x - 4) (9 x^{2} + 12 x + 16)

Distribute parentheses

= 3 x \cdot 9 x^{2} + 3 x \cdot 12 x + 3 x \cdot 16 - 4 \cdot 9 x^{2} - 4 \cdot 12 x - 4 \cdot 16

Simplify

3 x \cdot 9 x^{2} + 3 x \cdot 12 x + 3 x \cdot 16 - 4 \cdot 9 x^{2} - 4 \cdot 12 x - 4 \cdot 16 : 27 x^{3} - 64

= 27 x^{3} - 64

\frac{0.5 + 1}{2}

10 a^{6} - 30 a^{4} + 10 a^{2}

\frac{0.01 + 4 - 2}{0.01}

7 - 7

\frac{4 ^{2}}{4 ^{2}}

What is expand (3x-4)(9x^2+12x+16) ?
The solution to expand (3x-4)(9x^2+12x+16) is 27x^3-64