What are the solutions to the equation x^2-9x+1=0 ?

The solutions to the equation x^2-9x+1=0 are x=(9+sqrt(77))/2 ,x=(9-sqrt(77))/2

Find the zeros of x^2-9x+1=0

The zeros of x^2-9x+1=0 are x=(9+sqrt(77))/2 ,x=(9-sqrt(77))/2

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x^{2} - 9 x + 1 = 0

x = \frac{9 + 77}{2}, x = \frac{9 - 77}{2}

Decimal Notation

x = 8.88748 \dots, x = 0.11251 \dots

Solution steps

x^{2} - 9 x + 1 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 9 ) \pm ( - 9 ) ^{2} - 4 \cdot 1 \cdot 1}{2 \cdot 1}

(- 9)^{2} - 4 \cdot 1 \cdot 1 = 77

x_{1, 2} = \frac{- ( - 9 ) \pm 77}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 9 ) + 77}{2 \cdot 1}, x_{2} = \frac{- ( - 9 ) - 77}{2 \cdot 1}

x = \frac{- ( - 9 ) + 77}{2 \cdot 1} : \frac{9 + 77}{2}

x = \frac{- ( - 9 ) - 77}{2 \cdot 1} : \frac{9 - 77}{2}

The solutions to the quadratic equation are:

x = \frac{9 + 77}{2}, x = \frac{9 - 77}{2}

32 x^{3} + 16 x^{2} - 50 x - 25

2 - 2 m + [2 m - (2 - 2 m)] = 2

(x - 2) x - \frac{x + 2}{3} - \frac{( x - 2 ) ( x + 2 )}{2} = (x - 2)^{2} - 4

7 x + 8 - 9 (x + 1) = 3 x + 2

\frac{x ^{\frac{2}{5}} y}{x y ^{- \frac{1}{3}}}

What are the solutions to the equation x^2-9x+1=0 ?
The solutions to the equation x^2-9x+1=0 are x=(9+sqrt(77))/2 ,x=(9-sqrt(77))/2
Find the zeros of x^2-9x+1=0
The zeros of x^2-9x+1=0 are x=(9+sqrt(77))/2 ,x=(9-sqrt(77))/2