What is (x^2+2x-3)-(x^2+3x-4) ?

The solution to (x^2+2x-3)-(x^2+3x-4) is -x+1

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simplify (x^2+2x-3)-(x^2+3x-4)

simplify

(x^{2} + 2 x - 3) - (x^{2} + 3 x - 4)

- x + 1

Solution steps

(x^{2} + 2 x - 3) - (x^{2} + 3 x - 4)

Apply rule:

(a) = a

(x^{2} + 2 x - 3) = x^{2} + 2 x - 3

= x^{2} + 2 x - 3 - (x^{2} + 3 x - 4)

Apply the distributive law:

- (a + b) = - a - b

- (x^{2} + 3 x - 4) = - x^{2} - 3 x + 4

= x^{2} + 2 x - 3 - x^{2} - 3 x + 4

Group like terms

= x^{2} - x^{2} + 2 x - 3 x - 3 + 4

Add similar elements:

x^{2} - x^{2} = 0

= 2 x - 3 x - 3 + 4

Add similar elements:

2 x - 3 x = - x

= - x - 3 + 4

Add the numbers:

- 3 + 4 = 1

= - x + 1

- 5^{\frac{3}{2}}

6 \cdot (- \frac{2}{3})

\frac{4}{3} \cdot 12

\frac{( 2 x ^{2} ) ^{3}}{4 x ^{0}}

(4 x + 1) (3 x + 2)