What is (4x^2+2x-5)+(6x^2-x-5) ?

The solution to (4x^2+2x-5)+(6x^2-x-5) is 10x^2+x-10

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simplify (4x^2+2x-5)+(6x^2-x-5)

simplify

(4 x^{2} + 2 x - 5) + (6 x^{2} - x - 5)

10 x^{2} + x - 10

Solution steps

(4 x^{2} + 2 x - 5) + (6 x^{2} - x - 5)

Simplify

(4 x^{2} + 2 x - 5) + (6 x^{2} - x - 5) : 4 x^{2} + 2 x - 5 + 6 x^{2} - x - 5

= 4 x^{2} + 2 x - 5 + 6 x^{2} - x - 5

Group like terms

= 4 x^{2} + 6 x^{2} + 2 x - x - 5 - 5

Add similar elements:

4 x^{2} + 6 x^{2} = 10 x^{2}

= 10 x^{2} + 2 x - x - 5 - 5

Add similar elements:

2 x - x = x

= 10 x^{2} + x - 5 - 5

Subtract the numbers:

- 5 - 5 = - 10

= 10 x^{2} + x - 10

(a - 1) (b - 1)

6 m^{2} n - m n^{2}

(\frac{4 k ^{6}}{2 k ^{2}})^{4}

(7 x^{2} + 4 y^{3}) (7 x^{2} - 4 y^{3})

(x + 2)^{2} - 7 (x + 2) + 6

What is (4x^2+2x-5)+(6x^2-x-5) ?
The solution to (4x^2+2x-5)+(6x^2-x-5) is 10x^2+x-10