What is (0.09)^{(-1)/2} ?

The solution to (0.09)^{(-1)/2} is 10/3

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

simplify (0.09)^{(-1)/2}

simplify

(0.09)^{\frac{- 1}{2}}

\frac{10}{3}

Decimal Notation

3.33333 \dots

Solution steps

0.0 9^{\frac{- 1}{2}}

0.09 = \frac{9}{100}

= (\frac{9}{100})^{\frac{- 1}{2}}

Apply the fraction rule:

\frac{- a}{b} = - \frac{a}{b}

= (\frac{9}{100})^{- \frac{1}{2}}

Apply exponent rule:

a^{- b} = \frac{1}{a ^{b}}

= \frac{1}{( \frac{9}{100} ) ^{\frac{1}{2}}}

Apply radical rule:

(\frac{a}{b})^{c} = \frac{a ^{c}}{b ^{c}},

assuming

a \geq 0, b \geq 0

(\frac{9}{100})^{\frac{1}{2}} = \frac{9 ^{\frac{1}{2}}}{10 0 ^{\frac{1}{2}}}

= \frac{1}{\frac{9 ^{\frac{1}{2}}}{10 0 ^{\frac{1}{2}}}}

10 0^{\frac{1}{2}} = 10

= \frac{1}{\frac{9 ^{\frac{1}{2}}}{10}}

9^{\frac{1}{2}} = 3

= \frac{1}{\frac{3}{10}}

Apply the fraction rule:

\frac{1}{\frac{b}{c}} = \frac{c}{b}

= \frac{10}{3}

(2 - (- 1))^{\frac{1}{2}}

(1 + p) (3 - 2 p) (2 + 2 p)

x^{- 3} \cdot x

1.8 - (- 3.7)

\frac{26}{28}