What is ((8x^2+6x-20))/((4x-5)) ?

The solution to ((8x^2+6x-20))/((4x-5)) is 2x+4

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simplify ((8x^2+6x-20))/((4x-5))

simplify

\frac{( 8 x ^{2} + 6 x - 20 )}{( 4 x - 5 )}

2 x + 4

Solution steps

\frac{8 x ^{2} + 6 x - 20}{4 x - 5}

Factor

8 x^{2} + 6 x - 20 : 2 (4 x^{2} + 3 x - 10)

= \frac{2 ( 4 x ^{2} + 3 x - 10 )}{4 x - 5}

Factor

4 x^{2} + 3 x - 10 : (4 x - 5) (x + 2)

= \frac{2 ( 4 x - 5 ) ( x + 2 )}{4 x - 5}

Cancel the common factor:

4 x - 5

= 2 (x + 2)

Expand

2 (x + 2) : 2 x + 4

= 2 x + 4

\frac{t h rss}{h}

\frac{68}{12}

4 a^{3} - 6 a^{3} b

\frac{x ^{2} + 2 x - 3}{2 x ^{2} + x - 3}

\frac{255}{180}

What is ((8x^2+6x-20))/((4x-5)) ?
The solution to ((8x^2+6x-20))/((4x-5)) is 2x+4