What is (6-2i)/(4+i) ?

The solution to (6-2i)/(4+i) is 22/17-14/17 i

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simplify (6-2i)/(4+i)

simplify

\frac{6 - 2 i}{4 + i}

\frac{22}{17} - \frac{14}{17} i

Solution steps

\frac{6 - 2 i}{4 + i}

Multiply by the conjugate

\frac{4 - i}{4 - i}

= \frac{( 6 - 2 i ) ( 4 - i )}{( 4 + i ) ( 4 - i )}

Simplify

\frac{( 6 - 2 i ) ( 4 - i )}{( 4 + i ) ( 4 - i )} : \frac{22 - 14 i}{17}

= \frac{22 - 14 i}{17}

Rewrite in standard complex form:

\frac{22}{17} - \frac{14}{17} i

= \frac{22}{17} - \frac{14}{17} i

\frac{3}{2 7}

(x^{2} + 2 x)^{4}

∣ - 5 + 3 ∣

- \frac{5}{6}

- 2 \frac{3}{5}