What are the solutions to the equation (x-8)(x-6)=-1 ?

The solutions to the equation (x-8)(x-6)=-1 are x=7

Find the zeros of (x-8)(x-6)=-1

The zeros of (x-8)(x-6)=-1 are x=7

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(x - 8) (x - 6) = - 1

x = 7

Solution steps

(x - 8) (x - 6) = - 1

Expand

(x - 8) (x - 6) : x^{2} - 14 x + 48

x^{2} - 14 x + 48 = - 1

Move

1

to the left side

x^{2} - 14 x + 49 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 14 ) \pm ( - 14 ) ^{2} - 4 \cdot 1 \cdot 49}{2 \cdot 1}

(- 14)^{2} - 4 \cdot 1 \cdot 49 = 0

x_{1, 2} = \frac{- ( - 14 ) \pm 0}{2 \cdot 1}

x = \frac{- ( - 14 )}{2 \cdot 1}

\frac{- ( - 14 )}{2 \cdot 1} = 7

x = 7

The solution to the quadratic equation is:

x = 7

5 (x - 2) - 3 x \geq 3 (x + 2)

6 x - 1 = 5

\frac{x - 3}{2} - \frac{2 - x}{3} > 3

x (5 x - 9) = 14

4^{7} \times 4^{- 5}

What are the solutions to the equation (x-8)(x-6)=-1 ?
The solutions to the equation (x-8)(x-6)=-1 are x=7
Find the zeros of (x-8)(x-6)=-1
The zeros of (x-8)(x-6)=-1 are x=7