What is ((x^{-4}y^5)/5)^{-3} ?

The solution to ((x^{-4}y^5)/5)^{-3} is (125x^{12})/(y^{15)}

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simplify ((x^{-4}y^5)/5)^{-3}

simplify

(\frac{x ^{- 4} y ^{5}}{5})^{- 3}

\frac{125 x ^{12}}{y ^{15}}

Solution steps

(\frac{x ^{- 4} y ^{5}}{5})^{- 3}

Apply exponent rule:

a^{- b} = \frac{1}{a ^{b}}

(\frac{x ^{- 4} y ^{5}}{5})^{- 3} = \frac{1}{( \frac{x ^{- 4} y ^{5}}{5} ) ^{3}}

= \frac{1}{( \frac{x ^{- 4} y ^{5}}{5} ) ^{3}}

Simplify

(\frac{x ^{- 4} y ^{5}}{5})^{3} : \frac{y ^{15}}{125 x ^{12}}

= \frac{1}{\frac{y ^{15}}{125 x ^{12}}}

Apply the fraction rule:

\frac{1}{\frac{b}{c}} = \frac{c}{b}

= \frac{125 x ^{12}}{y ^{15}}

\frac{5}{7} \cdot \frac{2}{3}

\frac{1}{2} (1 - cos (2 x))

∣ 111 ∣

(p - 7)^{2}

What is ((x^{-4}y^5)/5)^{-3} ?
The solution to ((x^{-4}y^5)/5)^{-3} is (125x^{12})/(y^{15)}