What is factor p^3-pq^2+p^2q-q^3 ?

The solution to factor p^3-pq^2+p^2q-q^3 is (p+q)^2(p-q)

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factor p^3-pq^2+p^2q-q^3

factor

p^{3} - p q^{2} + p^{2} q - q^{3}

(p + q)^{2} (p - q)

Solution steps

p^{3} - p q^{2} + p^{2} q - q^{3}

= (p^{3} - p q^{2}) + (p^{2} q - q^{3})

Factor out

p

from

p^{3} - p q^{2} : p (p^{2} - q^{2})

Factor out

q

from

p^{2} q - q^{3} : q (p^{2} - q^{2})

= p (p^{2} - q^{2}) + q (p^{2} - q^{2})

Factor out common term

p^{2} - q^{2}

= (p^{2} - q^{2}) (p + q)

Factor

p^{2} - q^{2} : (p + q) (p - q)

= (p + q) (p - q) (p + q)

Apply exponent rule:

aa = a^{2}

(p + q) (p + q) = (p + q)^{2}

= (p + q)^{2} (p - q)

\frac{4}{5} \cdot 1

sin (x^{- 1})

(27 x^{6})^{\frac{4}{3}}

1 - 125 k^{3}

What is factor p^3-pq^2+p^2q-q^3 ?
The solution to factor p^3-pq^2+p^2q-q^3 is (p+q)^2(p-q)