What is factor x^2+1+2x ?

The solution to factor x^2+1+2x is (x+1)^2

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factor x^2+1+2x

factor

x^{2} + 1 + 2 x

(x + 1)^{2}

Solution steps

x^{2} + 1 + 2 x

Write in the standard form

= x^{2} + 2 x + 1

Rewrite in the form of

a^{2} + 2 ab + b^{2} :

1 = 1^{2}

2 x = 2 x \cdot 1

= x^{2} + 2 x \cdot 1 + 1^{2}

Apply Perfect Square Formula:

a^{2} + 2 ab + b^{2} = (a + b)^{2}

x^{2} + 2 x \cdot 1 + 1^{2} = (x + 1)^{2}

= (x + 1)^{2}

\frac{1}{16} \cdot \frac{4}{5}

(3 x - 1) (2 x + 4)

2 z - 2 w

- 2 x^{3} - 3 x^{2}

\frac{108}{( - 0.9 )}