What is factor 2d^3-4d^2-8d+16 ?

The solution to factor 2d^3-4d^2-8d+16 is 2(d-2)^2(d+2)

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factor 2d^3-4d^2-8d+16

factor

2 d^{3} - 4 d^{2} - 8 d + 16

2 (d - 2)^{2} (d + 2)

Solution steps

2 d^{3} - 4 d^{2} - 8 d + 16

Factor out common term

2 : 2 (d^{3} - 2 d^{2} - 4 d + 8)

= 2 (d^{3} - 2 d^{2} - 4 d + 8)

Factor

d^{3} - 2 d^{2} - 4 d + 8 : (d - 2) (d + 2) (d - 2)

= 2 (d - 2) (d + 2) (d - 2)

Apply exponent rule:

aa = a^{2}

(d - 2) (d - 2) = (d - 2)^{2}

= 2 (d - 2)^{2} (d + 2)

\frac{a ^{3}}{a ^{3}}

32 x^{6}

(X - 1) (X + 1)

12 + 15

\frac{1}{4} + \frac{7}{8}

What is factor 2d^3-4d^2-8d+16 ?
The solution to factor 2d^3-4d^2-8d+16 is 2(d-2)^2(d+2)