What is (15y^{-7})/(18y^{-3)} ?

The solution to (15y^{-7})/(18y^{-3)} is 5/(6y^4)

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simplify (15y^{-7})/(18y^{-3)}

simplify

\frac{15 y ^{- 7}}{18 y ^{- 3}}

\frac{5}{6 y ^{4}}

Solution steps

\frac{15 y ^{- 7}}{18 y ^{- 3}}

Factor the number:

15 = 3 \cdot 5

= \frac{3 \cdot 5 y ^{- 7}}{18 y ^{- 3}}

Factor the number:

18 = 3 \cdot 6

= \frac{3 \cdot 5 y ^{- 7}}{3 \cdot 6 y ^{- 3}}

Cancel the common factor:

3

= \frac{5 y ^{- 7}}{6 y ^{- 3}}

Simplify

\frac{y ^{- 7}}{y ^{- 3}} : \frac{1}{y ^{4}}

= \frac{5}{6 y ^{4}}

\frac{( - 3.9 ) ^{2} - 16}{( - 3.9 ) + 4}

2^{i}

3.19 \cdot 1 0^{5}

\frac{5 ^{- 8}}{5}

(x - 6) (x + 3 + 3)

What is (15y^{-7})/(18y^{-3)} ?
The solution to (15y^{-7})/(18y^{-3)} is 5/(6y^4)